Australia’s Ajla Tomljanovic is through to the fourth round of the Indian Wells tournament following a straight-sets win over number 26 seed Tamara Zidansek.
- Tomljanovic is through to the fourth round in Indian Wells for the first time in her career
- She will next face former world number one Angelique Kerber
- US Open winner Daniil Medvedev progressed to the round of 16 in the men’s draw
Tomljanovic — coming off an upset victory over fifth seed Garbine Muguruza — triumphed 6-4, 6-3 against Zidansek in one hour and 36 minutes.
Her win sets up a clash with former world number one and the 10th seed in Indian Wells, Angelique Kerber, in the round of 16.
Kerber won through after beating Russian 20th seed Daria Kasatkina 6-2, 1-6, 6-4.
Tomljanovic — ranked 47 in the world — has enjoyed an encouraging 2021 season.
She made an appearance in the Wimbledon quarter-finals, where she lost to countrywoman and eventual champion Ash Barty.
Tomljanovic had never previously made it past the second round in Indian Wells.
Meanwhile, women’s top seed Karolina Pliskova exited the tournament after going down to world number 115 Beatriz Haddad Maia 6-3, 7-5.
Fifteenth seed Coco Gauff lost to 21st-seeded Paula Badosa 6-2, 6-2, while defending champion Bianca Andreescu was beaten by Anett Kontaveit 7-6 (7-5), 6-3.
In the men’s draw, top-seeded Daniil Medvedev defeated Filip Krajinovic 6-2, 7-6 (7-1) to reach the round of 16.
Medvedev — who beat Novak Djokovic in the US Open final last month — connected on 70 per cent of his first serves and fired four aces, despite challenging weather conditions.
Among other men’s seeds to advance were Casper Ruud (six), Hubert Hurkacz (eight) and Diego Schwartzman (10).
But ninth seed Denis Shapovalov was beaten by Australian Open semi-finalist Aslan Karatsev 7-5, 6-2.